07-01-2017, 10:41 PM
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#4
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مشرف قسم CrossFire
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• الانـتـسـاب » May 2010
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• رقـم العـضـويـة » 70996
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• المشـــاركـات » 3,556
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• الـدولـة » مــصــر
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• الـهـوايـة » Silkroad Service
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• اسـم الـسـيـرفـر » Private Server
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• الـجـنـس » Male
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• نقـاط التقييم » 15
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رد: مشكله فى New Account
فى Table عندك اسمه _CharTrijob
اضغط عليه كليك يمين بعد كده Script Table As بعد كده Create To بعدها New Query Editor Window هتفتح معاك صفحه قارنها بينها وبين ديه وشوف لو فى حاجه ناقصه ولا لأ .
كود PHP:
USE [SRO_VT_SHARD] GO
/****** Object: Table [dbo].[_CharTrijob] Script Date: 07/01/2017 09:39:21 م ******/ SET ANSI_NULLS ON GO
SET QUOTED_IDENTIFIER ON GO
CREATE TABLE [dbo].[_CharTrijob]( [CharID] [int] NOT NULL, [JobType] [tinyint] NOT NULL, [Level] [tinyint] NOT NULL, [Exp] [int] NOT NULL, [Contribution] [int] NOT NULL, [Reward] [int] NOT NULL, CONSTRAINT [PK__CharTrijob] PRIMARY KEY CLUSTERED ( [CharID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON, FILLFACTOR = 90) ON [PRIMARY] ) ON [PRIMARY]
GO
ALTER TABLE [dbo].[_CharTrijob] ADD CONSTRAINT [DF__CharTrijob__JobType] DEFAULT ((0)) FOR [JobType] GO
ALTER TABLE [dbo].[_CharTrijob] ADD CONSTRAINT [DF__CharTrijob__Level] DEFAULT ((1)) FOR [Level] GO
ALTER TABLE [dbo].[_CharTrijob] ADD CONSTRAINT [DF__CharTrijob__Exp] DEFAULT ((0)) FOR [Exp] GO
ALTER TABLE [dbo].[_CharTrijob] ADD CONSTRAINT [DF__CharTrijob__Contribution] DEFAULT ((0)) FOR [Contribution] GO
ALTER TABLE [dbo].[_CharTrijob] ADD CONSTRAINT [DF__CharTrijob__Reward] DEFAULT ((0)) FOR [Reward] GO
ALTER TABLE [dbo].[_CharTrijob] WITH NOCHECK ADD CONSTRAINT [FK__CharTrijob__Char] FOREIGN KEY([CharID]) REFERENCES [dbo].[_Char] ([CharID]) GO
ALTER TABLE [dbo].[_CharTrijob] CHECK CONSTRAINT [FK__CharTrijob__Char] GO
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